question_answer 1)

Although geometries of \[N{{H}_{3}}\] and \[{{H}_{2}}O\]molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.

Answer:

In\[N{{H}_{3}}\], there is one lone pair on N-atom which repels bond pairs whereas in \[{{H}_{2}}O\], there are two lone pairs on O-atom which repel bond pairs. Thus, repulsion is more in\[{{H}_{2}}O\] than in \[N{{H}_{3}}\] and hence, the bond angle in water is less than in\[N{{H}_{3}}\].