11th Class Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना

  • question_answer 1)
      Write Lewis structure of the following compounds and show formal charges on each of them. \[HN{{O}_{3}},N{{O}_{2}},{{H}_{2}}S{{O}_{4}}\]

    Answer:

     
      Lewis Structures Formal Charges
    \[HN{{O}_{3}}\] \[H=1-\frac{1}{2}\times 2=0\] \[{{O}_{1}}=6-(4+\frac{1}{2}\times 4)=0\]\[{{O}_{2}}=6-(4+\frac{1}{2}\times 4)=0\]\[{{O}_{3}}=6-(6+\frac{1}{2}\times 2)=-1\]\[N=5-(\frac{1}{2}\times 8)=+1\]
    \[N{{O}_{2}}or{{N}_{2}}{{O}_{4}}\] \[{{O}_{1}}\And {{O}_{2}}=6-(4+\frac{1}{2}\times 4)=0\]\[{{O}_{3}}\And {{O}_{4}}=6-(6+\frac{1}{2}\times 2)=-1\]\[{{N}_{1}}\And {{N}_{2}}=5-(\frac{1}{2}\times 8)=+1\]
    \[{{H}_{2}}S{{O}_{4}}\] \[{{H}_{1}}\And {{H}_{2}}=1-\frac{1}{2}\times 2=0\] \[{{O}_{1}}\And {{O}_{2}}=6-(4+\frac{1}{2}\times 4)=0\]\[{{O}_{3}}\And {{O}_{4}}=6-(6+\frac{1}{2}\times 2)=-1\]\[S=6-(\frac{1}{2}\times 8)=+2\]
                     


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