Answer:
\[BC{{l}_{3}}\]\[s{{p}^{2}}\]-hybridisation
Triangular Planar
\[C{{H}_{4}}\]\[s{{p}^{3}}\]
-hybridisation Tetrahedral
\[C{{O}_{2}}\]\[sp\]-hybridisation
Linear
\[N{{H}_{3}}\]\[s{{p}^{3}}\]-hybridisation
Pyramidal
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