Answer:
(i) The first ionisation enthalpy of S
is less than that of P as S has unsymmetrical configuration and P has symmetrical
configuration.
P and N belong to the same
group. The atomic radius of P is more than N and thus, first ionisation
enthalpy of P is less than N.
O and N belong to same period
having atomic numbers 8 and 7 respectively. O has unsymmetric structure while N
has stable symmetrical configuration as each
p-orbital is half filled. Hence,
the ionisation enthalpy of O is less than N.
(ii) Non-metallic character
increases in a period and decreases in a group. Thus, the order is:
P < S < N < O.
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