question_answer 1)

At equilibrium the concentrations of \[[{{N}_{2}}]=3\times {{10}^{-3}}M,[{{O}_{2}}]=4.2\times {{10}^{-3}}M\]and\[[NO]=28\times {{10}^{-3}}M\]in a sealed vessel at 800 K. What will be \[{{K}_{c}}\] for the reaction: \[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)?\]

Answer:

The given reaction is: \[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)\] \[{{K}_{c}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}=\frac{{{(2.8\times {{10}^{-3}})}^{2}}}{3\times {{10}^{-3}}\times 4.2\times {{10}^{-3}}}\] \[=0.622M\]