question_answer 1)

The value of \[{{K}_{c}}\] for the reaction: \[2A\rightleftharpoons B+C\]is \[2\times {{10}^{-3}}\]. At a given time, the composition of reaction mixture is: \[[A]=[B]=[C]=3\times {{10}^{-4}}M\] In which direction, the reaction will proceed?

Answer:

The reaction is, \[2A\rightleftharpoons B+C\] \[{{K}_{c}}=2\times {{10}^{-3}}\] \[{{Q}_{c}}=\frac{[B][C]}{{{[A]}^{2}}}=\frac{3\times {{10}^{-4}}\times 3\times {{10}^{-4}}}{{{(3\times {{10}^{-4}})}^{2}}}=1\] \[{{Q}_{c}}>{{K}_{c}}\] Thus, reaction will proceed in backward direction.