Answer:
\[\mathbf{Base}\text{
}+\text{ }{{\mathbf{H}}^{+}}\to \text{ }\mathbf{Conjugate}\text{
}\mathbf{acid}\]
\[NH_{2}^{-}+{{H}^{+}}\to
N{{H}_{3}}\]
\[N{{H}_{3}}+{{H}^{+}}\to
NH_{4}^{+}\]
\[HCO{{O}^{-}}+{{H}^{+}}\to
HCOOH\]
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