question_answer 1)

What is the concentration of each of the substances in the equilibrium when the initial concentration of\[~ICl\] was 0.78M?

Answer:

The reaction is: \[\underset{\begin{smallmatrix} t=0 \\ {{t}_{eq}} \end{smallmatrix}}{\overset{{}}{\mathop{{}}}}\,\,\,\underset{\begin{smallmatrix} 0.78 \\ (0.78-2x) \end{smallmatrix}}{\mathop{2ICl(g)}}\,\rightleftharpoons \underset{\begin{smallmatrix} 0 \\ x \end{smallmatrix}}{\mathop{{{I}_{2}}(g)}}\,+\underset{\begin{smallmatrix} 0 \\ x \end{smallmatrix}}{\mathop{C{{l}_{2}}(g)}}\,\] \[{{K}_{C}}=\frac{[{{I}_{2}}][C{{l}_{2}}]}{{{[ICl]}^{2}}}\] \[0:14=\frac{x\times x}{{{(0.78-2x)}^{2}}}\] \[\sqrt{0.14}=\frac{x}{{{(0.78-2x)}^{2}}}\] \[0.374=\frac{x}{0.78-2x}\] \[x=0.167\] \[[{{I}_{2}}]=[C{{l}_{2}}]=0.167M\] \[[ICl]=0.78-2\times 0.167\] \[=0.446M\]