question_answer 1)

The solubility of\[Sr{{(OH)}_{2}}\]at 298 K is 19.23 g/L. Calculate the concentration of strontium, hydroxyl ions and the Ph of the solutions.

Answer:

Molar mass of \[Sr{{(OH)}_{2}}=88+34=122\] Molarity, \[M=\frac{Strength}{Molar\,mass}=\frac{19.23}{122}=0.16\] \[Sr{{(OH)}_{2}}\to S{{r}^{2+}}+2O{{H}^{-}}\] \[[S{{r}^{2+}}]=0.16M,\,\,[O{{H}^{-}}]=2\times 0.16=0.32M\] \[pOH=-\log [O{{H}^{-}}]\] \[=-\log [0.32]=0.49\] \[pH=14-pOH\] \[=14-0.49=13.51\]