question_answer 1)

The solubility product constant of\[A{{g}_{2}}Cr{{O}_{4}}\] and \[AgBr\] are \[1.1\times {{10}^{-12}}\]and \[5\times {{10}^{-13}}\]respectively. Calculate the ratio of molarities of their saturated solutions.

Answer:

Let solubility of\[A{{g}_{2}}Cr{{O}_{4}}\] and \[AgBr\]are \[{{s}_{1}}\]and \[{{s}_{2}}\] respectively \[4s_{1}^{3}=1.1\times {{10}^{-12}}\] \[s_{2}^{2}=5\times {{10}^{-13}}\] \[{{s}_{1}}=6.5\times {{10}^{-5}}\] \[{{s}_{2}}=7.07\times {{10}^{-7}}\] \[\frac{{{s}_{1}}}{{{s}_{2}}}=\frac{6.5\times {{10}^{-5}}}{7.07\times {{10}^{-7}}}=\frac{91.93}{1}\]