Answer:
(i) In
presence of peroxides, anti-Markownikoffs addition occurs and 1-bromohexane is
formed.
\[{{H}_{2}}C=\underset{Hex-1-ene}{\mathop{CHC{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,+HBr\]\[\xrightarrow[Peroxide]{In\,presence\,of}\underset{\underset{Br}{\mathop{|}}\,}{\mathop{{{H}_{2}}C}}\,-C{{H}_{2}}-C{{H}_{2}}-\underset{1-Bromohexane}{\mathop{C{{H}_{2}}-C{{H}_{2}}}}\,-C{{H}_{3}}\]
(ii) In absence of peroxides, Markownikoffs additionoccurs
and 2-bromohexane is formed.
\[{{H}_{2}}C=CH-\underset{Hex-1-ene}{\mathop{C{{H}_{2}}-C{{H}_{2}}}}\,-C{{H}_{2}}-C{{H}_{3}}+HBr\]\[\xrightarrow[Peroxide]{In\,presence\,of}\underset{{}}{\mathop{{{H}_{3}}C}}\,-\underset{\underset{\underset{2-Bromohexane}{\mathop{Br}}\,}{\mathop{|}}\,}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\]
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