question_answer 1)

Arrange the following: (i) \[Ca{{H}_{2}},Be{{H}_{2}}\] and \[Ti{{H}_{2}}\] in order of increasing electrical conductance. (ii) \[\text{LiH},\text{ NaH},\text{ CsH}\] in order of increasing ionic nature. (iii) HH, DD and FF in order of increasing bond dissociation energy. (iv) \[NaH,Mg{{H}_{2}}\] and \[{{H}_{2}}O\] in order of increasing reducing property.

Answer:

(i) \[Be{{H}_{2}}\] is a covalent hydride. Therefore, it does not conduct electricity. \[Ca{{H}_{2}}\] is an ionic hydride. Therefore, it conducts electricity in molten state. \[Ti{{H}_{2}}\] is a metallic hydride. Therefore, it is good conductor of electricity. \[\therefore \] Order of electrical conductance is: \[Be{{H}_{2}}