Answer:
Molecular mass of \[{{H}_{2}}{{O}_{2}}=34\]
Mass
of \[{{H}_{2}}{{O}_{2}}\] present in 1 molar solution = 34 g
Mass of \[{{H}_{2}}{{O}_{2}}\] present
in 2 litres of 1 molar solution
\[=2\times 34=68g\]
Mass of \[{{H}_{2}}{{O}_{2}}\]present
in 200 mL solution of 1 molar \[{{H}_{2}}{{O}_{2}}\] solution = \[\frac{34}{5}=6.8g\]
\[\underset{\begin{smallmatrix}
68g \\
6.8g
\end{smallmatrix}}{\mathop{2{{H}_{2}}{{O}_{2}}}}\,\to
2{{H}_{2}}O+\underset{\begin{smallmatrix}
32g \\
3.2g
\end{smallmatrix}}{\mathop{{{O}_{2}}}}\,\]
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