question_answer 1)

In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?

Answer:

Mass of organic compound, W = 0.157 g Mass of barium sulphate, \[{{W}_{1}}=0.4813g\] \[\underset{233g}{\mathop{BaS{{O}_{4}}}}\,\equiv \underset{32g}{\mathop{S}}\,\] Percentage of sulphur = \[\frac{32}{233}\times \frac{{{W}_{1}}}{W}\times 100\] \[=\frac{32\times 0.4813\times 100}{233\times 0.157}=\mathbf{42}\mathbf{.10%}\]