question_answer 1)

Draw formulae for the first five members of each homologous series beginning with the following compounds: (i) \[HCOOH\] (ii) \[C{{H}_{3}}COC{{H}_{3}}\] (iii) \[H-CH=C{{H}_{2}}\]

Answer:

(i)\[\mathbf{HCOOH}\text{ }:C{{H}_{3}}COOH,\text{ }C{{H}_{3}}C{{H}_{2}}COOH\], \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOH,\text{ }C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}\text{ }COOH\] (ii)\[\mathbf{C}{{\mathbf{H}}_{\mathbf{3}}}\mathbf{COC}{{\mathbf{H}}_{\mathbf{3}}}:C{{H}_{3}}C{{H}_{2}}COC{{H}_{3}},\]\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COC{{H}_{3}},\text{ }C{{H}_{3}}{{(C{{H}_{2}})}_{3}}COC{{H}_{3}},\]\[C{{H}_{3}}{{(C{{H}_{2}})}_{4}}COC{{H}_{3}}\] (iii)\[{{\mathbf{H}}_{\mathbf{2}}}\mathbf{C}=\mathbf{C}{{\mathbf{H}}_{\mathbf{2}}}:C{{H}_{3}}CH==C{{H}_{2}},\]\[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}},\text{ }C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}},\]\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}\]