Answer:
(c, d)\[\overset{0}{\mathop{Zn}}\,+2\overset{+1-1}{\mathop{HCl}}\,\to
\overset{+2-2}{\mathop{ZnC{{l}_{2}}}}\,+\overset{0}{\mathop{{{H}_{2}}}}\,\]
Zn (oxidised) ® Act as reductant
Hydrogen (reduced) ® Act as oxidant
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