question_answer 1)

  \[\text{PbO}\]and \[\text{Pb}{{\text{O}}_{\text{2}}}\]react with \[\text{HCl}\]according to following chemical equations : \[2PbO+4HCl\to 2PbC{{l}_{2}}+2{{H}_{2}}O\] \[Pb{{O}_{ & 2}}+5HCl\to PbC{{l}_{2}}+C{{l}_{2}}+2{{H}_{2}}O\] Why do these compounds differ in their reactivity?

Answer:

  \[\overset{+2-2}{\mathop{2PbO}}\,+4HCl\to 2\overset{+2-2}{\mathop{PbC{{l}_{2}}}}\,+2{{H}_{2}}O\] It is not a redox reaction; it is acid base reaction. \[\overset{+4-4}{\mathop{Pb{{O}_{2}}}}\,+4HCl\to 2\overset{+2-2}{\mathop{PbC{{l}_{2}}}}\,+C{{l}_{2}}+2{{H}_{2}}O\] It is a redox reaction in which lead is reduced.