Answer:
In an open vessel, pressure and volume
are always constant. Thus, we can use
\[{{n}_{1}}{{T}_{1}}={{n}_{2}}{{T}_{2}}\]
\[x\times
300={{n}_{2}}\times 750\]
\[{{n}_{2}}=x\times
\frac{300}{750}\]
\[{{n}_{2}}=x\times
\frac{2}{5}\]
2/5th of the gas is remaining,
hence 3/5th gas would have been expelled out.
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