question_answer 1)

Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

Answer:

Number of molecules \[=\frac{Mass}{Molar\,mass}\times 6.023\times {{10}^{23}}\] \[=\frac{1.4}{28}\times 6.023\times {{10}^{23}}=3.0115\times {{10}^{22}}\] Each molecule of \[{{N}_{2}}\] contains 14 electrons \[\therefore \] Number of electrons = \[3.0115\times {{10}^{22}}\times 14\] \[=4.216\times {{10}^{23}}\]