Answer:
Information
shadow:
P = 1 bar, \[R=0.083\text{
}bar\text{ L}{{\text{K}}^{-1}}mo{{l}^{-1}}\]
\[T=31.1+273=304.1K\]
\[n=\frac{8.8}{44}=0.2\]
\[V=?\]
Problem
solving strategy:
Ideal gas
equation can be used to calculate the volume of gas
\[PV=nRT\]
Working
it out:
\[1\times V=0.2\times 0.083\times 304.1\]
\[V=5.048L\]
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