Answer:
(a)
Boric acid at\[100{}^\circ \text{ }C\], gives metaboric acid.
\[{{H}_{3}}B{{O}_{3}}\xrightarrow{100{{\,}^{{}^\circ
}}C}HB{{O}_{2}}+{{H}_{2}}O\]
At\[160{}^\circ C\], it forms tetraboric acid.
\[4{{H}_{3}}B{{O}_{3}}\xrightarrow{160{{\,}^{{}^\circ
}}C}{{H}_{2}}{{B}_{4}}{{O}_{7}}+5{{H}_{2}}O\]
or\[4HB{{O}_{2}}\to
{{H}_{2}}{{B}_{4}}{{O}_{7}}+{{H}_{2}}O\]
When strongly heated, it forms boric anhydride or borontrioxide.
\[2{{H}_{3}}B{{O}_{3}}\to {{B}_{2}}{{O}_{3}}+3{{H}_{2}}O\]
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