Answer:
In\[B{{F}_{3}}\],
boron is\[s{{p}^{2}}-hybridized\], therefore, it has a planar shape. On the
other hand, in \[{{[B{{F}_{4}}]}^{-}}\] the boron is \[s{{p}^{3}}-hybridized\]and
hence, \[BF_{4}^{-}\] has a tetrahedral shape.
Planar \[(s{{p}^{2}}-hybridized)\] Tetrahedral \[(s{{p}^{3}}-hybridized)\]
You need to login to perform this action.
You will be redirected in
3 sec