Answer:
Heat evolved in the reaction
\[=-{{C}_{v}}\,\Delta
T\]
\[=-20.7\times
1=-20.7kJ\]
Heat evolved
in the combustion of 1 mole graphite, i.e.,12 g graphite will be:
\[\Delta U=-20.7\times 12kJ\,mo{{l}^{-1}}\]
\[=-2.48\times
{{10}^{2}}kJ\,mo{{l}^{-1}}\]
In the given
reaction: \[\Delta {{n}_{g}}=0\]
\[\therefore \]\[\Delta H=\Delta U=-2.48\times
{{10}^{2}}kJ\,mo{{l}^{-1}}\]
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