Answer:
Information shadow:
\[\Delta H=400\times
{{10}^{3}}J\,mo{{l}^{-1}}\]
\[\Delta
S=2000J{{K}^{-1}}mo{{l}^{-1}}\]
Problem
solving strategy:
A reaction
is spontaneous, when \[\Delta G=-ve\]
\[\therefore
\] \[(\Delta H-T\Delta S)\frac{\Delta
H}{\Delta S}\]
Working
it out:
\[T>\frac{400\times 1000}{2000}\]
\[T>200K\]
Reaction will be
spontaneous above 200 K.
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