Answer:
Let
y = f(x) = [x (x ? 2)]2 = (x2 ? 2x)2
= 2 (x2
?2x) (2x ? 2)
=
4x (x ?2) (x? 1)
f?(x)
= 0
Intervals
are :
When
f?(x)
= 0
Intervals
are :
When
f?(x)
= 4(?)(?)(?) < 0
When
f?(x)
= 4(+) (?)(?) > 0
When
f?(x)
= 4(+)(?) (+) < 0
When
f?(x)
= 4(+) (+)(+) > 0
is an
increasing function.
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