Answer:
f(x)
= x2 + ax + 1
Now
1 < x < 2
2 < 2x
< 4
2 + a
< 2x + a < 4 + a
2 + a
< f?(x) < 4 + a ?..(1)
f(x)
is strictly increasing on (1, 2), of f?(x) > 0
[Using
(1)]
Least
value of a = ?2.
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