12th Class Mathematics Continuity and Differentiability

  • question_answer 1)

    Answer:

    For x < ?1, f(x) is constant functions and is continuous, for x > ?1, f(x) is a polynomial function and is continuous.       At x = ? 1                                     Also f(?1) = ?2              Since LHL = RHL = f(?1)       Therefore f is continuous at x = ?1       Now for x < 1, f(x) is a polynomial function, so f is continuous, for x > 1, f(x) is constant function, so, f is continuous.                  At x = 1                                                f(1) = 2(1) = 2       Since LHL = RHL = f(1)       therefore f is also continuous at x = 1.        is a continuous function.  


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