Answer:
|A| =
= 1(0 ? 0) + 1
(9 + 2) + (0 ? 0) = 11
A11 =
(?1)1+1(0 ? 0) = 0;
A12 =
(?1)1+2(9 + 2) = ?11;
A13 =
(?1)1+3(0 ? 0) = 0;
A21 =
(?1)2+1(?3 ? 0) = 3;
A22 =
(?1)2+2(3 ? 2) = 1;
A23 =
(?1)2+3(0 + 1) = ?1
A31 =
(?1)3+1(2 ? 0) = 2;
A31 =
(?1)3+2(?2 ? 6) = 8;
A33 =
(?1)3+3(0 + 3) = 3
?.
(1)
and (adj A) A =
(adj A) A = 11
Also |A| I = 11
From (1), (2)
and (3), we get
A(adj A) = (adj
A) A = |A| I
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