Answer:
Objective
function is Z = ?x + 2y
L1
: x = 3 L3 : x + 2y = 6
L2
: x + y = 5
Here
Z is maximum at F(3, 2) and maximum value is 1 since the region is unbounded
therefore 1 may or may not be the maximum value of Z. For this draw graph of
inequality ? x + 2y > 1.
L
: ?x + 2y = 1
Since
the open half plane has points is common with the feasible region.
Z has no
maximum value.
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