question_answer 1)

Consider the experiment of throwing a die, if a multiple of 3 comes up, throw the die agains and if any other number comes, toss a coin. Find the conditional probability of the event ‘the coin shows a tail’ given that ‘atleast one die shows a 3’. 

Answer:

S = {(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6), (1, H), (2, H), (4, H), (5, H), (1, T), (2, T), (4, T), (5, T)}       Let A  = event that the coin shows a tail             = {(1, T), (2, T), (4, T), (5, T).       and B = event that atleast one die shows 3             B = {(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (6, 3)}                         For event B, N(S) = 0                              Required probability = P(A/B)