Answer:
S =
{(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (6, 1), (6, 2), (6, 3), (6,
4), (6, 5), (6, 6), (1, H), (2, H), (4, H), (5, H), (1, T), (2, T), (4, T), (5,
T)}
Let
A = event that the coin shows a tail
=
{(1, T), (2, T), (4, T), (5, T).
and
B = event that atleast one die shows 3
B
= {(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (6, 3)}
For
event B, N(S) = 0
Required
probability = P(A/B)
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