Answer:
Let
R1 = event of drawing a red ball in the first draw.
B2
= event of drawing a red ball in the second draw.
Before
first draw, we have total 10 balls [5R and 5B] and before second drawn we have
total 12 balls [either 7R and 5B are 7B]
Required
probability = P(R1 R2 or B1 R2)
= P(R1)
P) P(R2/R2) + P(B1) P(R2/B1)
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