Answer:
Since
Therefore,
0 + K + 2K + 2K + 3K + K2 + 2K2 + K = 1
9 K + 10K2 =1
10 K2 + 9K ?1 = 0
10 K2 + 10K ? K ?1 = 0
(K + 1)
(10K 2 1) = 0
10 K (K +
1) ? 1 (K + 1) = 0
K is
non-negative)
(i)
(ii) P(X
< 3)
=
P (X = 0) + (X = 1) + P (X = 2)
(iii) P (X > 6) =
P(X = 7) = 7K2 + K
(i) P(0 < X
< 3) = (X = 1) + P(X = 2)
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