Answer:
(i) \[4p+q+r\] \[(4p)\times (q+r)=(4p)\times (q)+(4p)\times (r)\] \[=4pq+4pr\] 8959781310 (ii) \[ab,\,a-b\] \[(ab)\times (a-b)=(ab)\times (a)-(ab)\times (b)\] \[={{a}^{2}}b-a{{b}^{2}}\] (iii) \[a+b,\,7{{a}^{2}}{{b}^{2}}\] \[(a+b)\times (7{{a}^{2}}{{b}^{2}})=(7{{a}^{2}}{{b}^{2}})\times (a+b)\] |by commutative law \[(7{{a}^{2}}{{b}^{2}})\times (a)+(7{{a}^{2}}{{b}^{2}})\times (b)\] \[=7{{a}^{3}}{{b}^{2}}+7{{a}^{2}}{{b}^{3}}\] (iv) \[{{a}^{2}}-9,\,4a\] \[({{a}^{2}}-9)\,\times (4a)=(4a)\times ({{a}^{2}}-9)\] | by commutative law \[=(4a)\times ({{a}^{2}})-(4a)\times (9)\] \[=4{{a}^{3}}-36a\] (v) \[pq+qr+2p,\,0\] \[(pq+qr+2p)\times (0)\] \[=(0)\times (pq+qr+2p)\] |by commutative law \[=(0)\times (pq)+(0)\times (qr)+(0)\]\[\times (2p)\] \[=0+0+0\] = 0.
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