question_answer 1)

Solve: (a) \[\therefore \] (b) \[=\frac{2}{21},\frac{2}{15},\frac{2}{11},\frac{2}{9},\frac{2}{8},\frac{2}{7}\] (c) \[\frac{7}{7}-\frac{5}{7}\] (d) \[\frac{4}{5},\frac{4}{6},\frac{4}{13},\frac{4}{2},\frac{4}{9},\frac{4}{11}\] (e) \[=13>11>9>6>5>2\] (f) \[\therefore \] (g) \[=\frac{4}{13},\frac{4}{11},\frac{4}{9},\frac{4}{6},\frac{4}{5},\frac{4}{2}\] (h) \[=\frac{4}{2},\frac{4}{5},\frac{4}{6},\frac{4}{9},\frac{4}{11},\frac{4}{13}\] (i) \[\frac{7}{11},\frac{7}{13},\frac{7}{5},\frac{7}{2},\frac{7}{3},\frac{7}{4}\] TIPS To add or subtract like fractions, we add the numerators or subtract the smaller numerator from greater numerator keeping denominator unchanged and then write in simplest form.

Answer:

(a) We have, \[=13>11>5>4>3>2\] [simplest form] (b) We have, \[\therefore \] [simplest form] (c) We have, \[=\frac{7}{13},\frac{7}{11},\frac{7}{5},\frac{7}{4},\frac{7}{3},\frac{7}{2}\] [simplest form] (d) We have, \[=\frac{7}{2},\frac{7}{3},\frac{7}{4},\frac{7}{5},\frac{7}{11},\frac{7}{13}\] [simplest form] (e) We have, \[\frac{12}{15}-\frac{7}{15}=\frac{12-7}{15}=\frac{5}{15}=\frac{1}{3}\] [simplest form] (f) We have, \[\frac{5}{8}+\frac{3}{8}=\frac{5+3}{8}=\frac{8}{8}=1\] [simplest form] (g) We have, \[1-\frac{2}{3}=\frac{3}{3}-\frac{2}{2}=\frac{3-2}{3}=\frac{1}{3}\] \[\frac{5}{6}\frac{2}{6},\] (h) We have, \[\frac{3}{6}0,\] [simplest form] (i) We have, \[\frac{1}{6}\frac{6}{6},\] \[\frac{8}{6}\frac{5}{6}\] \[=\frac{6}{8}\] [simplest form]