question_answer 1)

Fill in the boxes (a) \[\frac{1}{8},\frac{2}{8},\frac{3}{8},\frac{4}{8}\] (b) \[\frac{5}{8}.\] (c) \[\frac{1}{8},\frac{2}{8},\frac{3}{8},\frac{4}{8}\]

Answer:

(a) We have, \[\frac{5}{8}\] Here, \[\therefore \] is subtracted from missing fraction to get \[=\frac{5}{7}\] This means addition of \[\therefore \]and \[=\frac{5}{9}\]givens the missing fraction. \[=\frac{0}{10},\frac{1}{9},\frac{2}{8},\frac{3}{7}\] Missing fraction \[\frac{4}{6}.\] \[\frac{0}{4},\frac{1}{5},\frac{2}{6},\frac{3}{7}\] Now, \[\frac{4}{8}.\] Hence, \[\frac{1}{2}1\] (b) We have, \[\frac{3}{5}1\] Here, \[1\frac{7}{8}\] is subtracted from missing fraction to get \[\frac{4}{4}1\] This means addition of \[\frac{2005}{2005}1\] and \[\frac{1}{2}1\]givens the missing fraction. \[\frac{3}{5}1\] Missing fraction \[1\frac{7}{8}\] \[\frac{4}{4}1\][\[\frac{2005}{2005}1\]LCM of 2 and 5 = 10] \[\frac{1}{2},\frac{1}{4},\frac{3}{4},\frac{4}{4}\]or\[\frac{1}{8},\frac{2}{8},\frac{3}{8},\frac{7}{8}\] Hence, \[\frac{2}{5},\frac{3}{5},\frac{8}{5},\frac{4}{5}\] (c) We have, \[\frac{1}{2},\frac{1}{4},\frac{3}{4},\frac{4}{4}\] Here, missing fraction is subtracted from \[\frac{1}{2}=\frac{1\times 2}{2\times 2}=\frac{2}{4}\] to get\[\frac{1}{4}.\] This means addition of\[\frac{2}{4},3\] and missing fraction gives \[\frac{3}{4}\] So, we subtract \[\frac{4}{4}.\]from \[\frac{1}{8},\frac{2}{8},\frac{3}{8}\]to get missing fraction. \[\frac{7}{8}\] Missing fraction \[\frac{1}{8},\frac{2}{8},\frac{3}{8}\] We have, \[\frac{7}{8}.\] \[\frac{1}{8}.\] Missing fraction \[\frac{2}{8},3\] Hence, \[\frac{3}{8}\]