question_answer 1)

Find (a)\[(-7)-8-(-25)\] (b) \[(-13)+32-8-1\] (c)\[(-7)+(-8)+(-90)\] (d) \[50-(-40)-(-2)\]

Answer:

(a) \[(-7)-8-(-25)=(-7)+(-8)+25\] [\[\because \]Additive inverse of ?25 is 25] \[=-15+25=-15+15+10\]\[[\because 25=15+10]\] \[=0+10=10\] \[[\because -15+15=0]\] (b) \[(-13)+32-8-1=(-13)+32-9\] \[=-13+32+\](Additive inverse of 9) \[=(-13)+32+(-9)\] \[=-13-9+32=-22+32\text{ }\left[ \because 32=22+10 \right]\] \[=-22+22+10\] \[=0+10=10\] \[[\because -22+22=0]\] (c) \[(-7)+(-8)+(-90)=-15+(-90)=-105\] (d)\[50-(-40)-(-2)=50+\] (Additive inverse of ? 40) + (Additive inverse of ?2) \[=50+40+2=92\]