Answer:
Area of a tile \[=\frac{1}{2}\times {{d}_{1}}\times {{d}_{2}}\] \[=\frac{1}{2}\times 45\times 30\] \[=675\,c{{m}^{2}}\] \[\therefore \] Area of the floor \[=657\,\times 3,000\,c{{m}^{2}}\] \[=20,\,25,000\,c{{m}^{2}}\] \[=\frac{20,25000}{100\times 100}{{m}^{2}}\] \[=202.50\,{{m}^{2}}\] The cost of polishing per \[{{m}^{2}}=\text{Rs}\,4\] \[\therefore \] Total cost of polishing the floor \[=202\,.50\times 4\] = Rs 810.
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