question_answer 1)

The perimeter of a rectangle is 130 cm. If the breadth of the rectangle is 30 cm, find its length. Also find the area of the rectangle.

Answer:

                Perimeter of the rectangle \[=2\times (l\times b)\] \[\Rightarrow \]               \[130=2\times (l+30)\] \[\Rightarrow \]               \[l+30=\frac{130}{2}\] \[\Rightarrow \]               \[l+30=65\] \[\Rightarrow \]               \[l=65-30=3\text{5 cm}\] Hence, the length of the rectangle is 35 cm. Area of the rectangle \[=l\times b\] \[=\text{35}\times \text{3}0=\text{1}0\text{5}0\text{ c}{{\text{m}}^{\text{2}}}\] Hence, the area of the rectangle is \[\text{1}0\text{5}0\text{ c}{{\text{m}}^{\text{2}}}\].