Answer:
(a) Area of the parallelogram PQRS \[\text{= base }\!\!\times\!\!\text{ height = SR }\!\!\times\!\!\text{ QM}\] \[\text{= 12 }\!\!\times\!\!\text{ 7}\text{.6 c}{{\text{m}}^{\text{2}}}\text{ = 91}\text{.2 c}{{\text{m}}^{\text{2}}}\] (b) Area of the parallelogram PQRS \[=\text{base}\times \text{height}=\text{PS}\times \text{QN}\] \[\Rightarrow \] \[\text{91}\text{.2 = 8 }\!\!\times\!\!\text{ QN}\] \[\Rightarrow \] \[\text{QN =}\frac{\text{91}\text{.2}}{\text{8}}\text{ cm}\] \[\Rightarrow \] \[\text{QN = 11}\text{.4 cm}\text{.}\]
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