Answer:
(a) r = 14 mm \[\therefore \] Area of the circle \[=\pi {{r}^{2}}\] \[=\frac{22}{7}{{(14)}^{2}}=\frac{22}{7}\times 14\times 14=6\text{16 m}{{\text{m}}^{\text{2}}}\] (b) Diameter \[=\text{ 49 m}\] \[\Rightarrow \] Radius (r) \[=\frac{49}{2}\text{m}\] \[\therefore \] Area of the circle \[\text{=}\frac{22}{7}\times \frac{49}{2}\times \frac{49}{2}\text{ }{{\text{m}}^{\text{2}}}=\frac{3773}{2}\text{ }{{\text{m}}^{\text{2}}}=1886.5\text{ }{{\text{m}}^{2}}\] (c) \[\text{r = 5 cm}\] \[\therefore \] Area of the circle \[=\pi {{r}^{2}}=\frac{22}{7}{{(5)}^{2}}=\frac{22}{7}\times 5\times 5\] \[=\frac{550}{7}\text{ c}{{\text{m}}^{\text{2}}}\].
You need to login to perform this action.
You will be redirected in
3 sec