Answer:
Diameter of the table cover \[=\text{1}.\text{5 m}\] \[\Rightarrow \] Radius of the table cover (r) \[=\frac{1.5}{2}\text{m}\] \[\Rightarrow \] Circumference of the table cover \[=2\pi r\] \[\text{= 2 }\!\!\times\!\!\text{ 3}\text{.14 }\!\!\times\!\!\text{ }\frac{\text{1}\text{.5}}{\text{2}}\text{ m = 4}\text{.71m}\] \[\Rightarrow \] Length of the lace required \[\text{= 4}\text{.71 m}\] \[\therefore \] Cost of the lace = ` \[\text{4}.\text{71}\times \text{15}\] = ` 70.65
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