question_answer 1)

A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path.

Answer:

                                \[\text{PQ = 125 m + 3m + 3m = 131m}\]                 \[\text{QR = 65 m + 3m + 3m = 71 m}\]                 Area of the rectangle ABCD                 \[=l\times b=12\text{5 m  }\!\!\times\!\!\text{  65 m = }812\text{5 }{{\text{m}}^{\text{2}}}\]                 Area of the rectangle PQRS                 \[=l\times b=1\text{31 m  }\!\!\times\!\!\text{  71m}=930\text{1 }{{\text{m}}^{\text{2}}}\] \[\therefore \]                  Area of the path = Area of the rectangle PQRS ? Area of the rectangle ABCD \[=\text{93}0\text{1 }{{\text{m}}^{\text{2}}}-\text{ 8125 }{{\text{m}}^{\text{2}}}=\text{1176 }{{\text{m}}^{\text{2}}}.\]