question_answer 1)

Renu purchases two bags of fertiliser of weights 75 kg and 69 kg. Find the maximum value of weight, which can measure the weight of the fertiliser exact number of times.

Answer:

                For getting the maximum value of weight, we have to find out the HCF of 75 kg and 69 kg. i.e. 3 75 3 69 5 25 23 23 5 5 1 1 \[\therefore \] Prime factorisation of \[75=\times 5\times 5\] Prime factorisation of      \[69=\times 23\] Common factor of 75 and 69 is 3. Thus, HCF of 75 kg and 69 kg = 3 kg Hence, required maximum value of weight is 3 kg.