Answer:
For the longest tape, which can measure dimensions of room exactly, we have to find out the HCF of dimensions, i.e. 3 825 3 675 2 450 5 275 3 225 3 225 5 55 3 75 3 75 11 11 5 25 5 25 1 5 5 5 5 1 1
\[\therefore \] Prime factorisation of \[825=\times \times \times 11\] Prime factorisation of \[675=\times \times \times 3\times 3\] Prime factorisation of \[450=\times \times \times 3\times 2\] \[\therefore \] Common factors of 825, 675 and 450 are 3 and 5 (occurring twice). Thus, HCF of 825, 675 and \[450=3\times 5\times 5=75\] Hence, required measure of longest tape = 75 cm
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