Answer:
Here, maximum quantity of container will be equal to the HCF of 403, 434 and 465. 13 403 2 434 3 465 31 31 7 217 5 155 1 31 31 31 31 1 1 1
Prime factorisation of \[403=13\times \] Prime factorisation of \[434=2\times 7\times \] Prime factorisation of \[465=3\times 5\times \] Common factor of 403, 434 and 465 is 31. \[\therefore \] Maximum capacity of container = HCF of 403, 434, and 465 = 31 Litres
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