question_answer 1)

Draw a circle with centre C and radius 3.4 cm. Draw any chord AB. Construct the perpendicular bisector of \[{{l}_{1}}\]. and examine if it passes through C.

Answer:

                To construct the perpendicular bisector of chord \[{{l}_{2}}\], we use the following steps: Step I Draw a circle with C as centre and radius 3.4 cm. Step II Now, draw a chord \[{{l}_{2}},\] of the circle (a chord of a circle is a line segment joining any two points on the circle) Step III With A as .centre, using compasses draw an arc (here, we can draw circle also) with radius more than half of the length of \[{{l}_{2}}\]. Step IV With the same radius and with B as centre, draw an another arc using compasses. Let it cut the previous arc at P And C. Step V Join \[{{l}_{1}},{{l}_{2}},{{l}_{3}}\] and produced unto Q. It      Cuts \[{{l}_{4}}\] at O. Therefore,\[{{l}_{1}},{{l}_{2}},{{l}_{3}}\] is the     perpendicular bisector of \[{{l}_{4}}\].    Also, the perpendicular bisector \[{{l}_{1}},{{l}_{2}},{{l}_{3}}\]passes through the centre C of 1 the circle.                      Hence, the perpendicular bisector of chord AB passes through the centre C.