question_answer 1)

Find the value of:             (i) \[-4,\frac{2}{3}\]                         (ii) \[\frac{-3}{5}\div 2\]                (iii) \[\frac{-4}{5}\div -3\]                              (iv) \[-\frac{1}{8}\div \frac{3}{4}\] (v) \[-\frac{2}{13}\div \frac{1}{7}\]                           (vi) \[-\frac{7}{12}\div \left( \frac{-2}{13} \right)\]            (vii) \[\frac{3}{13}\div \left( \frac{-4}{65} \right)\]

Answer:

                (i) \[-4\div \frac{2}{3}=\frac{-4}{1}\div \frac{2}{3}=\frac{-4}{1}\times \frac{3}{2}=-\frac{4\times 3}{1\times 2}=-6\].                 (ii) \[\frac{-3}{5}\div 2=\frac{-3}{5}\div \frac{2}{1}=\frac{-3}{5}\times \frac{1}{2}=\frac{-3\times 1}{5\times 2}=\frac{-3}{10}\] (iii) \[\frac{-4}{5}\div -3=\frac{-4}{5}\div \frac{-3}{1}=\frac{-4}{5}\times \frac{1}{-3}=\frac{-4\times 1}{5\times (-3)}=\frac{4}{15}\] (iv) \[\frac{-1}{8}\div \frac{3}{4}=\frac{-1\times 4}{8\times 3}=\frac{-1}{6}\] (v) \[\frac{-2}{13}\div \frac{1}{7}=\frac{-2}{13}\times \frac{7}{1}=\frac{-14}{13}=-1\frac{1}{13}\] (vi) \[\frac{-7}{12}\div \left( \frac{-2}{13} \right)=\frac{-7}{12}\times \left( \frac{-13}{2} \right)\] \[=\frac{-7\times -13}{12\times 2}=\frac{91}{24}=3\frac{19}{24}\]                 (vii) \[\frac{3}{13}\div \left( \frac{-4}{65} \right)=\frac{3}{13}\times \left( \frac{65}{-4} \right)\]                 \[=\frac{3\times 65}{13\times (-4)}=\frac{-15}{4}=-3\frac{3}{4}\].