question_answer

Predict which out of the following species are planar. (i)\[NH_{4}^{+}\]                           (ii)\[CH_{3}^{+}\]                             (iii)\[S{{F}_{4}}\] (iv)\[O{{F}_{2}}\]                           (v)\[{{H}_{2}}O\]

Answer:

                                  The species will be planar if the central atom is \[s{{p}^{2}}\] hybridised. Let us calculate the hybridisation in all these species. (i)\[NH_{4}^{+}:\]\[H=1/2[5+4-1+0]=4\] (\[s{{p}^{3}}\]-non-planar) (ii)\[CH_{3}^{+}:\]\[H=1/2[4+3-1+0]\,=6/2=3\] (\[s{{p}^{2}}\]- planar) (iii)\[S{{F}_{4}}:\]\[H=1/2[6+4-0+0]=10/2=5\] (\[s{{p}^{3}}d\]- non-planar) (iv)\[O{{F}_{2}}:\]\[H=1/2[6+2-0+0]=8/2=4\] (\[s{{p}^{3}}\]- non-planar) (v)\[{{H}_{2}}O:\,\]\[H=1/2[6+2-0+0]\,=8/2=4\] (\[s{{p}^{3}}\]-non-planar)