question_answer

In cracking, C-C bonds cleave in preference to C-H bonds. Explain.

Answer:

                The bond dissociation enthalpy of C-C bond \[(355\,\,kJ\,mo{{l}^{-1}})\] is less as compared to that of C-H bond\[(414\,\,kJ\,mo{{l}^{-1}})\]. Therefore, in the cracking of alkanes, generally C-C bonds cleave to form smaller molecules.