Answer:
In aniline, the electron pair on the
amino group \[(-\overset{\centerdot \,\,\centerdot }{\mathop{N}}\,{{H}_{2}})\] co-ordinates
with \[AlC{{l}_{3}}\] (Lewis acid) to form a salt \[{{C}_{6}}{{H}_{5}}\overset{\oplus
}{\mathop{N}}\,{{H}_{2}}AlC{{l}_{3}}\]. As a result, the ring is not properly
activated and the Friedel Craft reaction does not take place.
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